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 lucittm Manassas, VA

Join Date: Apr 2007
Posts: 1,211
Garage
Here is what I discovered today:

1) I can't measure the 0.7 bar (10.15psi) stock spring - it's on the car
Spring Length = inch
Outer diameter = inch (Measured across middle coils with calipers)
Number of effective coils = (Two less than total coils)
Wire diameter = 0. inch (Measured at top near spring cut)
Installed height in WG = 2.5 inch (Estimated)
Computed spring rate = lb/inch

2) Next the 0.8 (11.60psi) bar spring -
Spring Length = 6.687 inch
Outer diameter = 2.70 inch
Number of effective coils = 6.75
Wire diameter = 0.198 inch
Installed height in WG = 2.5 inch
Computed spring rate = 43.38 lb/inch

3) Now the 1.0 (14.50psi) bar spring -
Spring Length = 6.750 inch
Outer diameter = 2.670 inch
Number of effective coils = 6.75
Wire diameter = 0.210 inch
Installed height in WG = 2.5 inch
Computed spring rate = 56.76 lb/inch

4) And the 1.1 (15.95) bar spring (Andial, I think) –
Spring Length = 6.937 inch
Outer diameter = 2.80 inch
Number of effective coils = 5.0
Wire diameter = 0.210 inch
Installed height in WG = 2.5 inch
Computed spring rate = 66.44 lb/inch

5) Finally the 1.2 (17.40) bar spring (If I had one...) –
Spring Length = inch
Outer diameter = inch
Number of effective coils =
Wire diameter = 0. inch
Installed height in WG = 2.5 inch
Computed spring rate = lb/inch

Used:
http://www.engineersedge.com/calculators/comp_spring_k_pop.htm

Mark
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1991 964 Polar Silver Metallic Turbo Coupe 02-22-2009, 09:06 AM #39 (permalink)