View Single Post
Speedy Squirrel Speedy Squirrel is offline
Rocket Scientist
 
Join Date: Jun 2008
Location: Detroit
Posts: 881
Displacement = 3.3L or 0.0033 cubic meters
Lambda 1 = 9.8 A/F
RPM = 5500
Boost = 1.2 Bar or 221 KPA absolute manifold pressure
Inlet Man temp = 35 C (just a guess, but typical) or 273 + 35 = 308 K
Gas Constant = 0.287 KJ/Kg*K

Mass of air = [(221)(0.0033)]/[(0.287)*(308)] = 0.00825 Kg of air for every 2 revs

(0.00825/2)*5500 = 22.7 kg/min or 1361 kg/hr or 3000 lb/hr of air

3000/9.8 = 306 lb/hr of fuel

306/6 = 51 lb/hr of fuel per injector

You are running way over 20% rich so you need at least 20% more fuel: 1.2 * 51 = 61.2 lb/hr

But you have 60 lb/hr injectors, so you're done.

You can go back to staring at pictures of boobs now.
Old 03-19-2010, 06:17 PM
  Pelican Parts Catalog | Tech Articles | Promos & Specials    Reply With Quote #26 (permalink)