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friday physics question
--this will surely be moved to parf--
If everyone aimed a laser pointer at the Moon at once, would it change color? given values...... everyone = 80% of all humans in the hemisphere vewing the moon sharks are not involved all laser pointers have a output of .005w and are red-- discuss- |
I think the sunlight on the moon would be too bright but I know nothing really.
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now, your stupid question: if the moon has an additional color shifted light source will the reflected color shift? yeah, if a politician promises more good and less bad, will some people believe it? |
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HA! I changed 'other question' to 'stupid question' when you did. :)
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If just one person pointed a laser at the moon it would change color... Photons would make their way to the moon surface and there is now more red light on the moon.
I think your real question is not if, but how much i.e. Would the color change be discernible to the human eye. |
No, but all the cats on earth would lose their minds.
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widebody FTW!
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Red-neck, wrassling fest will be 24/7! |
well...if you were to dissect this into a real physics problem, you'll have the following:
"If everyone aimed a laser pointer at the Moon at once, would it change color?" 1) the moon is only visible to 50% of the earth's surface at any one time 2) on that 50% of the surface, only 30% is land on average. 3) on that land portion, there'd a totally undeterminable number of human population. but if we assume a uniform distribution of human population of land (totally idiotic) across that land mass, we could at least have something. so 7bil population uniformly spread across perfectly spherical surface of earth. ~3.5billion can see the moon purely from line of sight, not taking into account surface toplogy, cloud cover, etc etc. ~3.5billion * 5mw laser pointers = 17.5 megawatt output. but this is only output, just the tip of the iceberg. since the population is spread uniformly across the applicable surface, the laser that's shining directly perpendicular to the surface of the earth is going to be closer to the moon than the laser that's shining tangent to the surface of the earth. within the earth atmosphere, the laser light will be refracted and diminished related to the distance traveled. additionally, temperature, humidity, pollution particulate matter content will all contribute to rob the laser beam of its power. even once the laser beam has exited the atmosphere, it still has to contend with space dust, although minutely. once it reaches the moon, once again, lunar atmosphere. once it reaches surface of the moon, how lunar rocks/dust reflect the laser beam will need to be taken account of. and again on the trip back to the earth, lunar atmo, space dust, earth atmo, and then finally perceived brightness on observer's retina. there's a whole lot of data and number crunching to be had. but it's just easier to use an existing item as a base. there are lunar observation reflectors are planted on the surface of the moon by apollo missions and by soviet missions too. according to wiki Lunar Laser Ranging experiment - Wikipedia, the free encyclopedia, "The reflected light is too weak to be seen with the human eye: out of 10^17 photons aimed at the reflector, only one will be received back on Earth every few seconds, even under good conditions." so given a return ratio of 1/10^17, and an output power of 17.5megawatt, you will only get to see 0.00000000017 watts returned. so no....you won't see a diff hehe |
My dad would call this a Rosebush Question. I used to drive him nuts when I was a kid with some of my questions, such as "If you dropped a bowling ball from an airplane and it landed next to a rosebush, would all the leaves fall off?"
I don't remember asking that particular question, but I do remember asking "If everyone on the planet dropped all their silverware on the floor at the same time, could you hear in on the moon?" Seriously drove him nuts. |
silverware/moon: no cause sound doesn't travel thru vacuum between Earth and Moon
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"Because GOD made it that way!!!" The car became very quiet after that... |
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My son has been asking crazy questions like this. Then, when I answer him as truthfully as I can, he asks his mother. :rolleyes:
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let's try it
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Dispersion would scatter the light before it could make the round trip visit and the sun's light would over power anything we could produce.
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Dr. Evil:
Any ways, the key to this plan is the giant laser. It was invented by the noted Cambridge physicist Dr. Parsons. Therefore, we shall call it the Alan Parsons Project. |
Don't think sorry's easily said
Don't try turning tables instead You've taken lots of Chances before But I ain't gonna give anymore Don't ask me That's how it goes Cause part of me knows what you're thinkin' Don't say words you're gonna regret Don't let the fire rush to your head I've heard the accusation before And I ain't gonna take any more Believe me The sun in your Eyes Chorus: I am the eye in the sky Looking at you I can read your mind I am the maker of rules Dealing with fools I can cheat you blind And I don't need to see any more To know that I can read your mind, I can read your mind Don't leave false illusions behind Don't Cry cause I ain't changing my mind So find another fool like before Cause I ain't gonna live anymore believing Some of the lies while all of the Signs are deceiving |
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My son replied: "oh, ok". "Dad, who's God??. I paused for a moment, the car became quiet. I replied " oh look, we are at your school". I will never forget that day. |
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If you aimed a laser at the moon, don't you need to caluculate the time it takes for the light to travel atthat distance and project where the moon would be at that time. You wouldn't aim the laser directly at the moon, would you?
Yes sound does not travel in a vaccum, however if a tree falls in the forest and no one is there, it doesn't make a sound either. |
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A better question would be If a man speaks and his wife is not there to hear him, is he still wrong? |
When my kids asked questions and I explained in detail, they lost interest and asked why I talked so much. :(
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No.
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It all depends on the quality of the hallucinogens involved.
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