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- is there an equation for this degrees to inches conversion? if so, can somebody post it?
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Randy:
The degrees-to-inches depends on the rolling diameter of the tire. My last post on this series of responses identifies a "graph" form of answer from Smart Racing Products..... Wil
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Wil Ferch 85 Carrera ( gone, but not forgotten ) |
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Thx Wil - I'll just make like an engineer and use the lookup .... ;-]
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Why did that feel like an insult? We Engineers know how to wield equations like a samurai his sword.
It's social grace that we lack. Td = invTAN (Ti / D) Where: Td = toe degrees Ti = toe inches D = tire diameter
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How's this for social grace ?
![]() The Smart Racing products "link" shows both the graph AND the formula....... Shall we put a bow-tie on this too ![]() ![]() Wil
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Wil Ferch 85 Carrera ( gone, but not forgotten ) |
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feel like an insult
Sorry! Not intended to insult engineers. Perhaps an implied insult to scientists - such as myself - who are never really happy until several experiments are done and they match theory, which in turn goes down to the quark level....
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I see where the confusion is coming in. (0.746059 vs .745997) The equation above assumes that 32' is the adjacent, where I assumed 32' was the hypotenuse.
I stand corrected. I think having the distance to the wall be one side, the 5" be the other side, and the remaining side be the hypotenuse is better than my way. I just got lucky that the triangle is such an acute right triangle. You guys are good.
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Boy, even on this BBS surveyors have a hard time getting respect.
Charlie is correct. The tangent angle = 5"(0.416666666...' say 0.416667, opposite) divided by 32' (adjacent, since it is the centerline of the car) = 0.746002605 degrees or 0 deg 44 min 45.6 sec. 1" = 1/12 of a ft = 0.0833333...' In the comps, you must convert inches to feet. Terry Hastings, L.S.
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Sounds just like a roomful of hardnosed en-gineers! Semantics, schmemantics... as long as Milt gets the beast off his patio and to the next meet without trashing his tires...Chuck gets us pics from the races...Steve finds a replacement for the missing '88... and I get my case put back together
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Milt,
I think he meant to say "Adjacent, since it is PARALLEL to the centerline of the car" Les
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Steve '08 Boxster RS60 Spyder #0099/1960 - never named a car before, but this is Charlotte. '88 targa ![]() |
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Excacalactly! That's what I derived from Milt's original description, if I understood him.
So Steve, every time I see that frown in your sig I wonder when it will go away...hope for the future ? ( you probably already explained it in another thread but... ) |
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This is a TOUGH crowd!!!!!!!!
Les is right, I assumed that the rear rotors were parallel to the centerline. By the way the difference is 0.2 seconds of angle, or about 0.0017' (or 0.5mm), so even in the P-car quality of engineering, both are correct. Terry
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Terry Hastings Baltimore, MD 1972 911T LTHSURVEY@AOL.com |
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