Throw Out Fork
 

I have searched and searched the forum and can't find the answer to this question: I am mating the engine (3.0 SC) to trans. (915) and see the top of the fork is aligned correctly in the groove. I can't see the bottom but assume it is lined up also. With the trans. bolted up to the engine, I went to test the resistance to rotation of the shaft of the TO fork to be sure it is properly mated. Are you supposed to be able to rotate the shaft? I put the small arm on the grooved shaft and used an adjustable wrench on the arm to get leverage. I can only move the thing very little; like it won't move at all. Are you supposed to be able to rotate the shaft? If so, how much force should it take? And, how far should it rotate? These are not new parts. Please advise.

Since you are trying to rotate the throw out fork without a helper spring, and essentially operating the clutch without leverage, its gonna take a lotta force to move it. I wouldn't attempt it, you'll risk stripping the spline on the shaft where your clutch lever arm goes on. As long as the fork is in the throwout bearing groove and it lines up, I wouldn't worry about it. I've had my 915 out twice and never recall an issue with this.

Maybe someone else can chime in...

If you have the starter off, you can reach inside the hole with your fingers and feel that you have it installed properly. I used this method when I put mine together.

Randy

Randy,

I beleive the fork is unstalled correctly. I am wondering how much torque it should take to actuate the clutch and how much rotational travel it (the shaft) should have. It seems like it takes an awful lot of force to actuate.

Jim

Yes, it takes an immense amount of force to operate. There is signifcant mechanical advantage with the clutch pedal, the 2 helper springs, and the lever arm. Sounds like you aren't doing anything wrong. You should have like a little "smidge" of rotation in the shaft and that's all.