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a fairly interesting excercise is to develop/understand for yourself the equation that converts torque to horsepower...
step 1 - convert torque (foot pounds) to energy per crankshaft revolution also foot pounds - this is sometimes a point of confusion setp 2 - multiply by crankshaft speed (revolutions per minute) this gives foot pounds per minute setp 3 - divide by 550 * 60 foot pounds per minute per hp. result = hp at that engine speed Example: rpm = 5000, torque = 100 ft - pounds force at 1 foot = 100 pounds force distance the force is applied = 1 foot * 2 * pi = 6.283 feet (the force is applied around the circumference of a circle) so the energy put out per revolution = 6.283 feet * 100 pounds = 628.3 foot pounds the energy put out per minute is 628.3 foot pounds per rev * 5000 rpm (revs per minute) = 3,141,590 foot pounds per minute the definition of a hp = 550 foot pounds per second or 33,000 foot pounds per minute the horse power at this rpm is therefore 3,141,590 foot pounds per minute / 33,000 foot pounds per minute per hp = 95.2 horse power |
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edit-- I see, maybe you are saying that the 200hp model has 33% less power than the 300hp model. |
more power
Steve,
Your math is correct. The actual "paper" calculations are 50% more power. How does this relate to a 911. Easy, drive a 3.2L and then borrow your brother-in-laws Turbo. It won't take math to obtain a clear understanding of the principle of "more power". SmileWavy |
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