Flieger |
06-21-2016 05:36 PM |
Quote:
Originally Posted by Bill Verburg
(Post 9169071)
+1
trying to calculate g for a stop is a futile task, variables include but are not limited to; variable μ, variable aero, variable tire μ, variable weight transfer, variable trans/diff/engine effects, variable human effects, variable road surface
the best that can be done w/o instrumentation is to calculate brake torque to get the ratios, w/ instrumentation you can correlate to the ratios but it's not really a fruitful endeavor.
The other factor that can be readily calculated is the hydraulic pedal ratio, this has a large effect on the brake feel, you can include mechanical pedal ratio w/ that to get an even better idea of what the brakes will feel like. Fortunately in the Porsche 911 world flex isn't as big an issue as w/ some other brands.
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For the purposes of spec'ing the brake system it is conventional to assume no tire lockup, and as a first approximation for non-hybrid and non-aero cars, no aero or engine braking effects. One still needs to make sure the bias is good at the same time, but the lbs/g is a useful parameter in my eyes. It is something that comes up in FSAE context.
It is a way of factoring in the fact that a lightweight car doesn't need as much mechanical advantage as a heavy one. The lbs/g is basically a final/overall mechanical advantage for you're leg effort. The tire friction will determine how many g's you can achieve but I'm interested in the ratio of leg force to deceleration, not the peak.
I think the original question was answered so I hope we don't mind this side bar? :confused:
I must admit that I'm looking at this for spec'ing a brake system from scratch on a small formula type car, so I'm just using 911 data for a reference of what feels good- which is why I am so interested in the lbs/g of deceleration. I can match that parameter and know the brakes should feel ok.
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