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-   -   FB 'Math' problem. (http://forums.pelicanparts.com/showthread.php?t=1057212)

71T Targa 04-07-2020 10:12 AM

FB 'Math' problem.
 
Please show your work.

I apparently don't know how to do basic math...

http://forums.pelicanparts.com/uploa...1586279418.jpg

gregpark 04-07-2020 10:14 AM

26
Can't show my work, it's a wild guess

tadd 04-07-2020 10:16 AM

Ugh, 45/3 = 15.
21/3 = 7
12/3 = 4

Thus 15+7=19*7=133

widebody911 04-07-2020 10:17 AM

Don't fall for these - the point isn't the math problem, it's harvesting users

https://blog.malwarebytes.com/101/2019/04/explained-like-farming/

KFC911 04-07-2020 10:20 AM

109 ...don't have any work :D

Otter74 04-07-2020 10:22 AM

There is an order for operations - you do multiplication and division first, then addition and subtraction, rather than simply doing the operations as they appear from left to right. So the answer is 109.

71T Targa 04-07-2020 10:25 AM

Some observations.
The image of the witch in the first row is not the same as in the last.
Not all of the broom images in the third row are the same.
The image of the wand in the second row doesn't match the image in the last row.


Quote:

Originally Posted by widebody911 (Post 10814850)
Don't fall for these - the point isn't the math problem, it's harvesting users

https://blog.malwarebytes.com/101/2019/04/explained-like-farming/

I promise not to harvest any users, and there isn't a link to FB (or anywhere else) in my post.

Sooner or later 04-07-2020 10:32 AM

4+15×7
4+(15×7)
4+105
109

stevej37 04-07-2020 10:33 AM

133 (no work..retired)

Paul T 04-07-2020 10:34 AM

Quote:

Originally Posted by widebody911 (Post 10814850)
Don't fall for these - the point isn't the math problem, it's harvesting users

https://blog.malwarebytes.com/101/2019/04/explained-like-farming/

^^This. Everyone should delete FB.

Steve Carlton 04-07-2020 10:34 AM

Kind of interesting with its subtleties. Looks like:

The wand = 7 each
There's 4 brooms that = 12, so they = 3 each
The witch with the broom and wand = 15
A witch w/o the broom and wand = 5

Bottom line would be 3 + (5 x 14) = 73

Sooner or later 04-07-2020 10:34 AM

Quote:

Originally Posted by 71T Targa (Post 10814862)
Some observations.
The image of the witch in the first row is not the same as in the last.
Not all of the broom images in the third row are the same.
The image of the want in the second row doesn't match the image in the last row.




I promise not to harvest any users, and there isn't a link to FB (or anywhere else) in my post.

Very good

tadd 04-07-2020 10:35 AM

...and that is why I am a chemist :-). Forgot about that pesky order of operations thing!

stomachmonkey 04-07-2020 10:39 AM

Quote:

Originally Posted by 71T Targa (Post 10814862)
Some observations.
The image of the witch in the first row is not the same as in the last.
Not all of the broom images in the third row are the same.
The image of the want in the second row doesn't match the image in the last row.




I promise not to harvest any users, and there isn't a link to FB (or anywhere else) in my post.

Exactly, in the third row the middle spoon is doubled up so that counts as 2X.

Last row the witch is missing the spoon (whose X needs to be added to the 1st row where she is holding it) and the wand is either doubled or tripled up.

It's a two part problem, find the differences and calculate the values accordingly then do the problem.

They can be fun if you like solving a puzzle but yes, harvesting. Best to just ignore or do offline if you are bored.

71T Targa 04-07-2020 10:55 AM

Quote:

Originally Posted by Steve Carlton (Post 10814877)
Kind of interesting with its subtleties. Looks like:

The wand = 7 each
There's 4 brooms that = 12, so they = 3 each
The witch with the broom and wand = 15
A witch w/o the broom and wand = 5

Bottom line would be 3 + (5 x 14) = 73

I 'like' this one. :D

masraum 04-07-2020 11:15 AM

Quote:

Originally Posted by widebody911 (Post 10814850)
Don't fall for these - the point isn't the math problem, it's harvesting users

https://blog.malwarebytes.com/101/2019/04/explained-like-farming/

Exactly, if you see something designed to either make you think you're smart (take this quiz, can you find the one item that's different, Can you figure out this problem, etc...) or list off places that you've been or your favorite stuff or take our quiz to find out how lovable you are or how cool you are or etc...., just ignore it.

71T Targa 04-07-2020 11:22 AM

There wasn't a link to follow for this one. Just a picture posted with 'friends' replying.

Not saying that this isn't for harvesting users... But it's not like the click bait quizzes I see.

red-beard 04-07-2020 12:37 PM

Quote:

Originally Posted by Steve Carlton (Post 10814877)
Kind of interesting with its subtleties. Looks like:

The wand = 7 each
There's 4 brooms that = 12, so they = 3 each
The witch with the broom and wand = 15
A witch w/o the broom and wand = 5

Bottom line would be 3 + (5 x 14) = 73

If this is the way to solve it....

broom line has THREE brooms, not FOUR

Broom = 4
Wand = 7
Witch with Broom and wand = 15
Witch alone = 15-4-7 = 4

4 + (4 x 7) = 32

1990C4S 04-07-2020 12:45 PM

Quote:

Originally Posted by Steve Carlton (Post 10814877)
Kind of interesting with its subtleties. Looks like:

The wand = 7 each
There's 4 brooms that = 12, so they = 3 each
The witch with the broom and wand = 15
A witch w/o the broom and wand = 5

Bottom line would be 3 + (5 x 14) = 73

Isn't it 3 brooms=12, i.e. four each?

So the 'base' witch is 15-7-4=4 also?

Bottom line is 4+4x7=32

Maybe.

gtc 04-07-2020 12:51 PM

If you look closely, there appears to be a second broom behind the middle one, as well as a second wand in the last formula.

Quote:

Originally Posted by red-beard (Post 10815029)
If this is the way to solve it....

broom line has THREE brooms, not FOUR

Broom = 4
Wand = 7
Witch with Broom and wand = 15
Witch alone = 15-4-7 = 4

4 + (4 x 7) = 32


stevej37 04-07-2020 12:56 PM

two wands in the last pic also. ;)

Steve Carlton 04-07-2020 01:23 PM

There's a second layer of complexity in it, which is pretty obvious when you look at it closely. It catches people not paying close attention. I credit 71T Targa for busting it wide open.

Zeke 04-07-2020 02:49 PM

I go with RB except using his reasoning I come up with 17.

3 wands value each = 7
4 brooms value each = 3
Bottom row: 2 wands + 1 broom.

1990C4S 04-07-2020 02:58 PM

Quote:

Originally Posted by stevej37 (Post 10815067)
two wands in the last pic also. ;)

I can't see that, but I'm old and the picture is intentionally fuzzified.

MBAtarga 04-07-2020 05:34 PM

Quote:

Originally Posted by Steve Carlton (Post 10814877)
Kind of interesting with its subtleties. Looks like:

The wand = 7 each
There's 4 brooms that = 12, so they = 3 each
The witch with the broom and wand = 15
A witch w/o the broom and wand = 5

Bottom line would be 3 + (5 x 14) = 73

How many brooms?

Zeke 04-07-2020 05:43 PM

Quote:

Originally Posted by MBAtarga (Post 10815412)
How many brooms?

4. 2 and a double image.

rattlsnak 04-07-2020 11:17 PM

Quote:

Originally Posted by Steve Carlton (Post 10814877)
Kind of interesting with its subtleties. Looks like:

The wand = 7 each
There's 4 brooms that = 12, so they = 3 each
The witch with the broom and wand = 15
A witch w/o the broom and wand = 5

Bottom line would be 3 + (5 x 14) = 73

This is correct..

svandamme 04-08-2020 12:51 AM

The Question is http://forums.pelicanparts.com/uploa...1586332298.jpg

flatbutt 04-08-2020 09:17 AM

Quote:

Originally Posted by tadd (Post 10814879)
...and that is why I am a chemist :-). Forgot about that pesky order of operations thing!

although there are times when "order of addition" is critical. Ever made emulsions?

Steve Carlton 04-08-2020 11:59 AM

This one is more challenging, but not too difficult:

http://forums.pelicanparts.com/uploa...1586372331.jpg

stevej37 04-08-2020 12:16 PM

Quote:

Originally Posted by flatbutt (Post 10816027)
Ever made emulsions?

Yep..lots of them in college. Liquor was cheap then. :)

dad911 04-08-2020 12:52 PM

Quote:

Originally Posted by steve carlton (Post 10816300)
this one is more challenging, but not too difficult:

http://forums.pelicanparts.com/uploa...1586372331.jpg

012

Steve Carlton 04-08-2020 02:35 PM

You broke the second rule.

gordner 04-08-2020 02:45 PM

102

Eric Coffey 04-08-2020 02:45 PM

Quote:

Originally Posted by gordner (Post 10816533)
102

Breaks rule #3.

Has to be: 042

john70t 04-08-2020 04:19 PM

On the original question:

All 3 witches,X on the top row are carrying a star wand,Y and a broom,Z.
3X+3Y+3Z = 45
(assume addition, instead of a multiplier or a different symbol)

All 3 star wands are the same.
3Y=21
Star wand =7

There are actually 4 brooms in the third row. I didn't notice at first.
(assume addition, instead of a multiplier or a different symbol)
4Z=12
Broom= 3

Going back to the first line to find value of the witch, X:
45 - three wands(=21) - three brooms(=9) = 15. 15 divided by three witches is 5.
Witch = 5.

So 7 + 3 + 5 =15

Alan A 04-08-2020 04:26 PM

042

Edit nm already answered.

Eric Coffey 04-08-2020 04:42 PM

Quote:

Originally Posted by john70t (Post 10816631)
So 7 + 3 + 5 =15

Your numbers for the individual items is correct. However, there are 2 wands in final equation, and the later action is x not +.

So considering PEMDAS it's: 3+(5x14)=73

(Steve nailed in on post #11).

;)

john70t 04-08-2020 06:04 PM

I first got 102 until I re-read #3.
Eric is right. Again..

Danimal16 04-08-2020 06:14 PM

Quote:

Originally Posted by gtc (Post 10815047)
If you look closely, there appears to be a second broom behind the middle one, as well as a second wand in the last formula.

Good catch.


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