Help with torsion bar calulations please

[911st]

I am trying to understand how much sway bars contribuite to the wheel rate.

Can someone help figure out the following torsion bar/ lever length's in pounds per inch?

38" torsion bar length with a 13.5" lever on one end in the following diamters:

25mm
24mm
22mm
21mm
19mm

38" torsion bar length with a 10" lever:

25mm
24mm
22mm
20mm
19mm
18mm

Thank you very much if you can help.

[Roc Doc]

SAW used to have an effective spring rate calculator on their website. You'd need to know the spring rate of each spring though.

[jess p]

Visit rennlist.com,go to technical forums,then suspension and torsion bars. Has all the
formulas.

[911st]

Thank you for the input guys.

I wish I had the math skills to do it myself. Once I get past percentages, compounding, and or the volume of a circle I start to get lost.

I need help.

[burgermeister]

k = (3.14159*d^4 * 80000 / (32 * bar_length)) * ( 25.4) / (4.448 * lever_length^2))
bar length, lever length, and radius in mm

pi* d^4 * G / (32*L) is the stiffness in N*mm/radian (G = 80000 MPa, pi = 3.14159...)
/ lever_length^2 converts to linear stiffness (N/mm)
* 25.4/4.448 converts to pounds / inch

Assuming I didn't brainfart something ....

Edit: Brainfarts indeed ... and lots of them ... have been corrected. I Think. That's what I get when not resorting to reference material.

[911st]

Thanks Burgermeister.

That is all greek to me but thanks.