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T_Samner T_Samner is offline
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Join Date: Oct 2006
Posts: 46
Quote:
Originally posted by mikester
So, you have to figure the permutation of each card.

You have hte permutation of 3 of 4 kings possible in a hand of 5 cards;

P(4,3)

and then the permutation of 2 of 4 queens possible in a hand of 5 cards;

P(4,2)

And the Rule of product says those answers should be multiplied;

P(4,3) * P(4,2)

P(n,m) = n!/(n-m)! or in Excell simply =PERMUT(n,m)

So, we get 24 * 12 = 288.

If order did not matter then it would be a matter of combination and not permutation.

C(4,3) * C(4,2)

C(n,m) = P(n,m)/m! or in Excel =combin(n,m)

4 * 6 = 24 different unordered combinations possible.

Next time do your own math homework.

Nope. Incorrect.
Old 10-29-2006, 10:25 PM
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