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T_Samner T_Samner is offline
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Join Date: Oct 2006
Posts: 46
Quote:
Originally posted by Zero10



there are 288 ways for each configuration, and there are...... 10? ways to arrange it, so 2880 configurations?

Winner!



If the numbers 1 through five represent the order in which a card is drawn, then the 3 kings could have been drawn as the first, second and third cards drawn or the first second and fourth cards drawn etc. for a total of C(5,3) = 10 unique orders of drawing a king. For each of these 10 unique groups representing the order in which a king could be drawn there are P(4,3) = 24 ways of assigning the four different kings to a position in the group for a total of C(5,3) x P(4,3) = 240 different possible ways to draw a king. Finally, there are P(4,2) = 12 ways of getting a queen for the 2 remaining cards for a total of C(5,3) x P(4,3) x P(4,2) = 2880.

Last edited by T_Samner; 10-30-2006 at 12:30 AM..
Old 10-30-2006, 12:26 AM
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