[mikester]

Originally posted by T_Samner
Winner!



If the numbers 1 through five represent the order in which a card is drawn, then the 3 kings could have been drawn as the first, second and third cards drawn or the first second and fourth cards drawn etc. for a total of C(5,3) = 10 unique orders of drawing a king. For each of these 10 unique groups representing the order in which a king could be drawn there are P(4,3) = 24 ways of assigning the four different kings to a position in the group for a total of C(5,3) x P(4,3) = 240 different possible ways to draw a king. Finally, there are P(4,2) = 12 ways of getting a queen for the 2 remaining cards for a total of C(5,3) x P(4,3) x P(4,2) = 2880.

That doesn't seem correct to me at all; I stand by my answer. I'll send it to my Math prof though and see what he has to say.