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Un Chien Andalusia
Join Date: Oct 2006
Location: Bay Area, SF, CA
Posts: 2,679
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Had to edit my answer when I read the post again, but with a set size = n, the combination size = k then:
Number of permutations (P)= n!/k!(n-k)!
Which is what jriera said below...
Where the ! denotes 'Factorial' which is the product of the number and all positive intergers below that number. So for 39! that would be 39x38x37xetc....x3x2x1
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Last edited by Aerkuld; 09-10-2007 at 02:10 PM..
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