Quote:
Originally Posted by Jim Richards
"b" isn't a function because it has two possible values of F(x) at x=0.
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Correct. Both (a) and (c) are functions, because for any value of x (the independent variable) there is one and one one value of F(x), therefore, they fit the basic rule of being a function.
(b) isn't a function, because there is a case where there are 2 values of F(x) for a single value of x...therefore, it breaks the rule.