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SlowToady SlowToady is offline
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Problem and post edited, because the the answer is rather beyond "arithmetic" and I'd probably just look like a dick for posting it, even though on the face of the problem it is not difficult. (The solution is difficult, though.)

Quote:
Originally Posted by cab83_750 View Post
I am arithmetic impaired:

3 guys went to the bar agreeing to pay the tab equally.
The bill was exactly $30.00

$30 divided by 3 is $10.00 per person
The waitress collected $10 from Person A, $10 from Person B, $10 from Person C.
Waitress went to the cashier. Cashier said "Hey those guys received $5.00 discount."
Waitress realized she could not split $5.00 three ways equally so she pocketed $2.00.
She returned $1 to Person A, $1 to Person B, and $1 to Person C.

Person A initially paid $10.00; received $1.00 back; so Person A actually paid $9.00
Person B also actually paid $9.00
Person C is also $9.00

$9.00 times 3 = $27.00
$27.00 plus $2.00 the waitress pocketed = $29.00

Where in the heck is the missing $1.00?
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Last edited by SlowToady; 10-21-2008 at 05:30 AM..
Old 10-21-2008, 05:19 AM
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