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Back in the saddle again
Join Date: Oct 2001
Location: Central TX west of Houston
Posts: 57,063
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< edit > I screwed up again, thanks dad911 < /edit >
This is more difficult, but it still works out the same way. Getting the measure of a side when the area is 16 is messier with the correct formula (assuming you can't use a calculator and give the answer in decimals).
16 = √3/4•sē
s = 8/fourth root of 3
s' = looking for
A = 16
A' = 4
A = √3/4•sē
A' = √3/2•ss'
s' = 2A'/(s•√3)
s' = 8/(8/(fourth root of 3)•√3)
Assuming I didn't screw up again....
s' = 1/fourth root of 3
Sheesh, I hope that's right, but having to use the fourth root would be unusual for most math classes
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Steve
'08 Boxster RS60 Spyder #0099/1960
- never named a car before, but this is Charlotte.
'88 targa  SOLD 2004 - gone but not forgotten
Last edited by masraum; 04-20-2009 at 04:48 PM..
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