Quote:
Originally Posted by RWebb
C = 2 pi r, where r= 3
= 6 pi total distance around
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Yeah, that's what I got, but it's not really relevant in this case. The question is how many rotations (360° or 2π) will the small coin need to get back to the point where it started. Well, the circumference of the small coin will wrap around the large coin 3 times, but that's not 3 rotations, thats 4 full rotations.
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