Quote:
Originally Posted by aways
One night while bored, I "discovered" the following relation (turns out it's well known; not original to me):
The sum of the cubes of the first N integers is equal to the square of the sum of the first N integers.
For example, take N=3:
{Sum_i=1 to 3} i^3 = [{Sum_i=1 to 3}]^2
1 + 8 + 27 = [1+2+3]^2
36 = 36
Can anybody prove the general relation?
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Not me. This works for any value of N?