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Almost Banned Once
Join Date: Feb 2009
Location: Adelaide South Australia
Posts: 38,941
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Theoretically you're right but in practice there may a small voltage drop when applying double the resistance but you would defiantly get way more current.
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Just for info, I use this formula for determining the value of a resistor for using LEDS.
When using a Light Emitting Diode (LED) as an indicator, use the following formula to determine series resistance for various voltages:
R = (E - 1.7) x 1000/I,
Where R is the resistance in ohms, E is the supply voltage (DC) and I is the LED current in milliamps.
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- Peter
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