Quote:
Originally Posted by winders
There is a convention that says you do implicit multiplication before division. Based on that convention, you get:
48÷2(9+3) = n
48÷2(12) = n
48÷24 = n
n = 2
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You begin correctly with:
48÷2(9+3) = n
48÷2(12) = n
48÷24 = n then at this step you err.
48÷2(12) = n is the same as
48÷2*12 = n
BY CONVENTION, you then proceed from left to right, the first operation is division:
24*12= n
and THEN multiplication:
n= 288,
not
n = 2[/QUOTE]
Quote:
Originally Posted by winders
...Also, you word problem doesn't match your results.
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Oops.I made a typo, corrected below:
"Question - What number do you end up with when you divide 48 by 2, then multiply that number by the sum of 9+3? Express this question in the form of an algebraic equation and show each step of your work."
Answer - the equation is 48÷2(9+3) = n (or 48/2(9+3) = n).
The steps to solving for n are:
48÷2(9+3) = 48÷2(12) = 48÷2x12 = 24x12 = n = 288
As per the rules of math, you begin at the left, performing the first operation, 48/2=24.
Then you perform the second operation, which is to multiply 24 by the sum of the numbers inside the parentheses, which is 12.
24*12=288
Nothing unclear, nothing ambiguous, nothing to argue about.
Hope this finally clears up this basic algebra confusion for you.
