FB 'Math' problem.

[71T Targa]

Please show your work.

I apparently don't know how to do basic math...

[gregpark]

26
Can't show my work, it's a wild guess

[tadd]

Ugh, 45/3 = 15.
21/3 = 7
12/3 = 4

Thus 15+7=19*7=133

[widebody911]

Don't fall for these - the point isn't the math problem, it's harvesting users

https://blog.malwarebytes.com/101/2019/04/explained-like-farming/

[KFC911]

109 ...don't have any work

[Otter74]

There is an order for operations - you do multiplication and division first, then addition and subtraction, rather than simply doing the operations as they appear from left to right. So the answer is 109.

[71T Targa]

Some observations.
The image of the witch in the first row is not the same as in the last.
Not all of the broom images in the third row are the same.
The image of the wand in the second row doesn't match the image in the last row.

Originally Posted by widebody911

Don't fall for these - the point isn't the math problem, it's harvesting users

https://blog.malwarebytes.com/101/2019/04/explained-like-farming/

I promise not to harvest any users, and there isn't a link to FB (or anywhere else) in my post.

[Sooner or later]

4+15×7
4+(15×7)
4+105
109

[stevej37]

133 (no work..retired)

[Paul T]

Originally Posted by widebody911

Don't fall for these - the point isn't the math problem, it's harvesting users

https://blog.malwarebytes.com/101/2019/04/explained-like-farming/

^^This. Everyone should delete FB.

[Steve Carlton]

Kind of interesting with its subtleties. Looks like:

The wand = 7 each
There's 4 brooms that = 12, so they = 3 each
The witch with the broom and wand = 15
A witch w/o the broom and wand = 5

Bottom line would be 3 + (5 x 14) = 73

[Sooner or later]

Originally Posted by 71T Targa

Some observations.
The image of the witch in the first row is not the same as in the last.
Not all of the broom images in the third row are the same.
The image of the want in the second row doesn't match the image in the last row.




I promise not to harvest any users, and there isn't a link to FB (or anywhere else) in my post.

Very good

[tadd]

...and that is why I am a chemist :-). Forgot about that pesky order of operations thing!

[stomachmonkey]

Originally Posted by 71T Targa

Some observations.
The image of the witch in the first row is not the same as in the last.
Not all of the broom images in the third row are the same.
The image of the want in the second row doesn't match the image in the last row.




I promise not to harvest any users, and there isn't a link to FB (or anywhere else) in my post.

Exactly, in the third row the middle spoon is doubled up so that counts as 2X.

Last row the witch is missing the spoon (whose X needs to be added to the 1st row where she is holding it) and the wand is either doubled or tripled up.

It's a two part problem, find the differences and calculate the values accordingly then do the problem.

They can be fun if you like solving a puzzle but yes, harvesting. Best to just ignore or do offline if you are bored.

[71T Targa]

Originally Posted by Steve Carlton

Kind of interesting with its subtleties. Looks like:

The wand = 7 each
There's 4 brooms that = 12, so they = 3 each
The witch with the broom and wand = 15
A witch w/o the broom and wand = 5

Bottom line would be 3 + (5 x 14) = 73

I 'like' this one.

[masraum]

Originally Posted by widebody911

Don't fall for these - the point isn't the math problem, it's harvesting users

https://blog.malwarebytes.com/101/2019/04/explained-like-farming/

Exactly, if you see something designed to either make you think you're smart (take this quiz, can you find the one item that's different, Can you figure out this problem, etc...) or list off places that you've been or your favorite stuff or take our quiz to find out how lovable you are or how cool you are or etc...., just ignore it.

[71T Targa]

There wasn't a link to follow for this one. Just a picture posted with 'friends' replying.

Not saying that this isn't for harvesting users... But it's not like the click bait quizzes I see.

[red-beard]

Originally Posted by Steve Carlton

Kind of interesting with its subtleties. Looks like:

The wand = 7 each
There's 4 brooms that = 12, so they = 3 each
The witch with the broom and wand = 15
A witch w/o the broom and wand = 5

Bottom line would be 3 + (5 x 14) = 73

If this is the way to solve it....

broom line has THREE brooms, not FOUR

Broom = 4
Wand = 7
Witch with Broom and wand = 15
Witch alone = 15-4-7 = 4

4 + (4 x 7) = 32

[1990C4S]

Originally Posted by Steve Carlton

Kind of interesting with its subtleties. Looks like:

The wand = 7 each
There's 4 brooms that = 12, so they = 3 each
The witch with the broom and wand = 15
A witch w/o the broom and wand = 5

Bottom line would be 3 + (5 x 14) = 73

Isn't it 3 brooms=12, i.e. four each?

So the 'base' witch is 15-7-4=4 also?

Bottom line is 4+4x7=32

Maybe.

[gtc]

If you look closely, there appears to be a second broom behind the middle one, as well as a second wand in the last formula.

Originally Posted by red-beard

If this is the way to solve it....

broom line has THREE brooms, not FOUR

Broom = 4
Wand = 7
Witch with Broom and wand = 15
Witch alone = 15-4-7 = 4

4 + (4 x 7) = 32