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What's the length of this rope
or, umm, wire. Need to get these on FBMP. I'm not unraveling and measuring.
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On the spool, can you read the markings on the end sticking out of the hole?
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Markings on the wire Vinny? Yes, they are what you see in the third pic. My guess is at least 60% of the spool is gone.
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There was 500 lineal feet on the wooden spool, but it’s used, so no telling how much now. Maybe 100’ now?
On the Romex, the box says 250’ if not used. |
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Thanks, box is used too.
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Shaun check if you can see the footage marking near the end by the center hole if possible, then check the footage marking on the loose end.
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Cut a foot
Weigh it Calculate length based on weight after subtracting an estimated weight for the spool. Alternately, remove the spool for a more precise measure |
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First thing I do tomorrow, thanks, now I get it.
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THat is a really good idea, thanks. I think it will only work for the box, can't imagine what that spool will weigh.
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Count the coils, multiply by pi*d
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Normally when it's spooled like that, it's starts at zero ft, then is marked as it is loaded on. The last ft marking on the loose end is most likely the actual footage left on the spool.
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I thought about that and it would be easy for the wire in the box. For the wire on the spool, there would be more work involved.
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Twice the distance from its midpoint to its end
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By the way Shaun, that white awg12 may come in handy some day. Especially if you want to make a new 'repair' in an older house look like it was existing.
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The low voltage spool has feet marked on it, I can see 278ft on a section and 250ft on another, so check both ends and do some math.
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Thanks, I thought of that too for the box but I really like the weigh 1 foot idea as well given the variable diamaters.
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Quote:
Good eye Rutager, thanks.
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Per Google...
12/3 romex weighs .107 lb/ft. 14 AWG 2/C E57497 unshielded weighs .037 lbs/ft typical plywood weigh about 35 lbs per cubic foot
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Measure diameter of outer coil, estimate diameter of arbor, take average of those diameters as D, divide half the difference in diameter by diameter of one wire as N, count number of coils visible on surface as C, (2 * pi * D/2) * N * C is estimated length of wire.
Do all of the methods discussed in thread and let us know what the results are and what the actual length is.
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Or you could just look the the footage printed on the cable......
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