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ckissick's Avatar
 
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7th grade math problem

For you mathematicians:

You drive 135 miles in 3 hours. You drive at a speed of 55 mph part of the time, and 40 mph the other part of the time. How much time do you spend at each speed?

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Charlie
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Old 02-25-2014, 08:44 PM
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66 min @55 for 60 miles
114 min @40. For 76 miles

If you round to full min. You will actually cover 136 miles in 3 hrs at these time/speeds.
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Old 02-25-2014, 08:56 PM
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Show your work, or no credit!
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Charlie
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Old 02-25-2014, 08:59 PM
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How about 55 for 1 hour and 40 for 2
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Old 02-25-2014, 09:00 PM
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Yeah Doug methinks thou dost try waaaaay too hard.
Old 02-25-2014, 09:06 PM
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distance = rate * time
t1 = time at 55 mph t2 = time at 40

t1 * 55 + t2 * 40 = 135

t1 + t2 = 3 or t2 = 3 - t1

substitute 2 into 1
t1 * 55 + (3 - t1) * 40 = 135
t1 * 55 - 40 * t1 = 15
t1 = 1
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Old 02-25-2014, 09:06 PM
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Now calculate the redshift for those speeds and how much you have travelled into the future after the three hours have elapsed in your frame of reference.
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Old 02-25-2014, 09:07 PM
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Quote:
Originally Posted by ckissick View Post
Show your work, or no credit!
I am going to show Ricks work because I like his answer

55mph x 1hr = 55 miles
40mph x 2hrs = 80miles

1 + 2 = 3 hrs
55+80 = 135

The marketing side is just trying to go the extra mile.
The math side of me says, don't do math with an ipad calculator and no paper while it's late at night.
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Old 02-25-2014, 09:09 PM
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Of course, my daughter is in algebra, so I was thinking in terms of two algebra equations, substituting, etc. But maybe Rick's Occum's Razor method is the way to go.
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Old 02-25-2014, 09:23 PM
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Is this a real 7th grade problem of your kid? Where did it come from?

Rick-l has the analytical solution.

That said, a keen eye will see that 135 in 3h is an average of 45 and that you can get there by trial and error. More 40 mph time is needed, so let's try 2*40 + 55 and voila ...

G
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Old 02-25-2014, 10:25 PM
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Simple, once you figure it out correctly....

d = rt

Part of the 135 mile trip was taken at 55 MPH and the other part was taken at 40 MPH. So we have two related distance equations to solve.

Let's solve for the 55 MPH part of the trip.

The part of the trip taken at 55 MPH equates to this:

d = 55t

The part of the trip taken at 40 MPH, relative to the other part, looks like this:

135 - d = 40(3 - t)

Add them together: 135 = 55t + 40(3 - t)

Now simplify and solve for t:

135 = 55t + 120 - 40t

135 = 15t + 120

15 = 15t

t = 1

So, the 55 MPH part of the trip took 1 hour so the 40 MPH part took 2 hours. 1 hour at 55 MPH and 2 hours at 40 MPH equal 135 miles.

We can prove it by solving it the other way around.

The part of the trip taken at 40 MPH equates to this:

d = 40t

The part of the trip taken at 55 MPH, relative to the other part, looks like this:

135 - d = 55(3 - t)

Add them together: 135 = 40t + 55(3 - t)

Now simplify and solve for t:

135 = 40t + 165 - 55t

135 = -15t + 165

-30 = -15t

t = 2

So, the 40 MPH part of the trip took 2 hours which matches up perfectly with what we did above.
Old 02-26-2014, 12:32 AM
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Most 7th graders would say f-this and go over to the Chest Thread. I recommend you all remove your pocket protectors and do the same.

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Old 02-26-2014, 12:58 AM
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What, can't we do both??

By the way, I never got a word problem like this in 7th grade....I am not sure I got one like this in high school either!

Last edited by winders; 02-26-2014 at 02:21 AM..
Old 02-26-2014, 02:06 AM
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Actially, kids these days would probably just google the question as a first step in figuring out the problem.

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Old 02-26-2014, 02:36 AM
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This statement makes no sense:

Quote:
You drive at a speed of 55 mph part of the time, and 40 mph the other part of the time.
How did I get from zero to 55? Or from 55 to 40? Clearly, there must have been a nearly infinite amount of additional speeds that were driven. Besides, when have I ever driven 135 miles an not exceeded 55 mph? The answer is: "never."

I would submit the question back to the "teacher" for revision. There are far too many people that blindly accept this type of indoctrinated interrogation from so-called "authority" figures, without questioning that "authority." Leads to very bad things.
Old 02-26-2014, 03:57 AM
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Johnny's mother had three children.
The eldest is named April.
The second eldest is named May.
What is the name of the third child?
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Old 02-26-2014, 04:32 AM
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Old 02-26-2014, 04:34 AM
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Old 02-26-2014, 12:31 PM
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I was thinking how I've never run into this, or any of the other stupid word problems we were graded on since...

...I left high school.
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Old 02-26-2014, 12:41 PM
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Quote:
Originally Posted by 911saucy View Post
i was thinking how i've never run into this, or any of the other stupid word problems we were graded on since...

...i left high school.
^ +1

Old 02-26-2014, 12:52 PM
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