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T77911S 12-14-2015 02:16 AM

Quote:

Originally Posted by wwest (Post 8915383)
Oops, sorry, I was wrong

PELICAN CAN SHUT DOWN!!!!!

i have the imortal words that NO ONE has ever seen or heard.

T77911S 12-14-2015 02:25 AM

Quote:

Originally Posted by Jonny H (Post 8914687)
As I have stated all along, the downstream stuff is completely irrelevant to the current draw of the unit. I fully understand what you are saying about the secondary HT rising blah blah, but it makes jack all difference to the current that the box uses.

THIS THREAD IS ABOUT THE CURRENT DRAW OF THE UNIT.

You said that the current draw increased with load (cylinder pressure). I said false.

You just agreed that the capacitor is charged to a fixed voltage and this does not change with load.

That means that energy required to charge it always the same, irrespective of load.

Therefore:

THE CURRENT DRAW IS THE SAME IRRESPECTIVE OF LOAD.

Do you agree with that statement?

arguing with west is like arguing with a 15yr old.
you are talking about the origianal subject but west (the 15yr old) has changed topics and is now arguing something else, meantime you think the topic is still the original subject.

makes me think of the argument with my 15 yr this weekend.
i tell him to get up 5 or 6 times, then through a glass of water on him.
he gets mad at me because he was JUST ABOUT to get up......1/2 an hour after i told him to get up. and yet he cant understand why i had to through water on him.

T77911S 12-14-2015 02:26 AM

i have a question for west.

WHAT IS THE CURRENT DRAW OF A BOSCH CD??

rick-l 12-14-2015 08:10 AM

Quote:

Originally Posted by Jonny H (Post 8909513)
That is not very nice insulting me is it? What have I done to harm you, exactly?

Don't take it personally.

I 'm thinking WWEST lives in his own little world where he makes minor alterations the laws of physics as he goes along to explain his understanding. That and he'll find buzzwords and acronyms that barely apply to the situation and act like they are physical laws. He'll never admit he was wrong and of course in later discussion he will use the opposing side if it enhances his argument.

He might be forgetting that the coil is a transformer and the energy is transferred to the spark in the gap. The opposite voltage excursion is caused by the magnetization inductance of the core and stores a minor amount of energy.

rick-l 12-14-2015 08:54 AM

I wonder if C16 and R10 make a snubber or if they are there to limit the dv/dt on the anode of the SCR.

not much current flows through those reverse biased diodes or the switched off SCR.
Quote:

Originally Posted by Early_S_Man (Post 1972197)
Here is the 1973 version schematic:

http://forums.pelicanparts.com/uploa...1138499120.jpg
[/img]


wwest 12-14-2015 10:47 AM

Quote:

Originally Posted by rick-l (Post 8917360)
I wonder if C16 and R10 make a snubber or if they are there to limit the dv/dt on the anode of the SCR.

not much current flows through those reverse biased diodes or the switched off SCR.

dv/dt.. Yes.

Note that the charge path for the 1.4uF capacitor is through the coil primary (inductive) and therefore the flyback type inverter output rise-time would fairly fast absent the RC snubber.

"..not much current..."

The linked article indicates that in the case of inverter output "bridge" rectification the peak REVERSE current flow (plug fired) will be 8 to 12 amps, brand/model dependent, 1:100 ratio.

In the case of the Bosch OEM the inverter secondary is in the reverse current flow path.

A. The rate of rise of the reverse current is restricted inductively.
B. The inverter secondary's (relatively low) resistance will limit the reverse peak current.
C. The coil's inductance + the primary winding inductance along with the capacitor form a resonant circuit which extends the duration of the reverse current pulse.

Without the loss of the energy to fire the plug a second time there will be more energy to be returned to the capacitor charge, OEM coil ~5mJ, E & I coil ~8mJ.

wwest 12-14-2015 12:56 PM

Quote:

Originally Posted by Jonny H
Mr West,

I'm not going to post anymore on the thread, I've had enough.

On an purely technical level, I would just like to point out that in the 'worldphaco' scope trace, the design under test is different to the Bosch CDI.

Yes, as I said, the 3rd of the 3 simplistic diagrams most closely matches the Bosch design provided you remove the clamp diode that diverts the ~5mJ (8mJ for the Accel 140008) back into the 12 volt buss, the energy that would otherwise go to recharging the capacitor.

If you compare the Bosch and 'worldphaco' traces, you will see that the 'worldphaco' design does an extra half-cycle (negative going) before the inverter switches on.

My point, exactly. Please refer to the coil secondary current traces, 140ma initial plug firing, 80ma subsequent plug firing. In the Bosch design it is this second firing cycle that is "forced" into the circuit path to recharge the capacitor.

Either way, the cap is always fully discharged in both designs prior to 'recharging', therefore the energy used to charge it and thus the current is the same regardless of 'load'.

If this were not the case and the energy were 'saved', the first trace after switching the ignition on would look different to subsequent ones wouldn't it? It can assure you it is exactly the same.

"..I can assure you..."

HOW.??

I wish you well.

Cheers

Jonny

SmileWavy

wwest 12-14-2015 01:36 PM

Please read the below document, most especially the last paragraph..

"...Now that the capacitor...."

Author concludes, as scope trace indicates, that the capacitor is recharged to -100 volts even though a portion of the energy was used to create a second arc.



http://forums.pelicanparts.com/uploa...1450132174.jpg

rick-l 12-14-2015 03:04 PM

Hey WW
If there is 200 volts across C5 and C16 in the above schematic is there the possibility C5 has 1.4 Volts across it and C16 198.6?

Jonny H 12-14-2015 03:07 PM

The last paragraph refers to a different design where the author is describing the fall from 200V to -100V where indeed the cap discharges to the primary.

In the Bosch design, that half cycle doesn't occur, compare it to the one you posted:

http://i804.photobucket.com/albums/y...psktgjqkw4.png

See? It is truncated.

Instead, the inverter switches on at the top of the 200V and the trace plummets to zero. At this point the cap is negatively charged, it does not get a chance to discharge to the coil as the inverter shorts it out, before charging it again. If it did, you would see the discharge and it would look like the top green trace you posted.

When I said in my PM to you 'I can assure you' it was because I measured it on the scope with our CDI test rig. While I was at it, I also looked at the primary and secondary rise time in detail at 10ns. As you corrected stated, the secondary rise time and firing voltage does change with load (I widened the gap). But, as I have said all along, it does not affect the primary in any way, the rise time is 10ns or thereabout irrespective of load.

How about you do some of your own experiments if you still disagree?

I am very careful about posting on forums, unless I have real world experience of the subject matter. Not just reading stuff but actual real life involvement. My company has been immersed in the design of a brand new CDI unit for the last two years. Although myself and coworkers are MEng EE qualified, I admit power electronics never really featured in our usual line of work. The reason we teamed with a power electronics company was to learn! I like learning and forums are a great way to do that.

I wouldn't dare to comment about building gearboxes, suspension geometry or panel work, all of which I am utterly useless at.

I also prefer the medium of clear English when trying to convey information. 'Blinding folks with science' and technical 'showboating' is just a bit sad really as it serves no purpose. People will look back on this thread and the good information will be lost in a sea of jargon and 'willy waving'.

Ronnie's.930 12-14-2015 03:27 PM

Quote:

Originally Posted by Jonny H (Post 8917945)
. . . and 'willy waving'.

You are now one of my forum heros - well done! :D

PS - have you ever read any of the past a/c theads - they mirror this one.

wwest 12-14-2015 05:57 PM

Quote:

Originally Posted by rick-l (Post 8917939)
Hey WW
If there is 200 volts across C5 and C16 in the above schematic is there the possibility C5 has 1.4 Volts across it and C16 198.6?

Across, as in from the D1 cathode to ground? I'll assume so.

The 2 capacitors are in parallel circuit legs....

At the instant you apply 200 volts via the inverter, yes, you have very little voltage drop across C5, it's a virtual short, with the remainder imposed across the coil primary inductance. C16 would also be a virtual short at this instant, so the majority of the 200 volts would be measured across R10.

Bob Kontak 12-14-2015 06:09 PM

Quote:

Originally Posted by Jonny H (Post 8917945)
I wouldn't dare to comment about building gearboxes, suspension geometry or panel work, all of which I am utterly useless at.

I also prefer the medium of clear English when trying to convey information. 'Blinding folks with science' and technical 'showboating' is just a bit sad really as it serves no purpose. People will look back on this thread and the good information will be lost in a sea of jargon and 'willy waving'.

Ronnie. This man has brains and humility. A righteous dude.

Technical "showboating". OMG. Six years of wrestling with the "Dub" and even Eric never uttered this term in rebuttal. Spot on.

Clear English when trying to convey info? Yep.

The sad part truly is wwest could be and educator. He is not. I don't get it. Sunset years. Probably well heeled. Needs to beat on Jonny. Needs to beat on Dave or Rick1 or Charlie. Experienced guys. For what end? His ego? Six years worth of ego boosting needed when in his later 70's? He's smart, but he ain't Grady Clay Porsche smart.

Fifty squillion time I (we) have asked Willy to throttle it back. No change.

Why?

Bob Kontak 12-14-2015 06:18 PM

Quote:

Originally Posted by rick-l (Post 8917291)
I 'm thinking WWEST lives in his own little world where he makes minor alterations the laws of physics as he goes along to explain his understanding.

How many time would a rational person need to hear this feedback before taking inventory?

Just shift gears, Willy. I know you are the straight man. Be a nice man, instead.

dicklague 12-14-2015 07:40 PM

QUOTE OF THE YEAR ON PP:


"WWEST lives in his own little world where he makes minor alterations the laws of physics as he goes along to explain his understanding."

Ronnie's.930 12-14-2015 08:34 PM

Quote:

Originally Posted by Bob Kontak (Post 8918200)

Fifty squillion time I (we) have asked Willy to throttle it back. No change.

Why?

Bobusmaximus, you know the answer (and have said it yourself before); Mr. West likes to mud wrestle regardless of how much he knows about the mud he's rolling in. :)

T77911S 12-15-2015 05:45 AM

question for WEST

how much current does a bosch CD draw???

i too have worked on many radars:
MPN-14
TPN-19
GPN-20

ASR-8
ASR-11

he reminds me of a radar tech i use to work with.
he would spout off 7 or 8 impressive bits of radar info but never would work on anything.

rick-l 12-15-2015 08:09 AM

I don't know why but this is for Wild Willy on why very little energy is returned to the storage capacitor.

The CDI coil is a transformer. Ideally, a transformer stores no energy. Energy is transferred immediately from input to output.
All physically realizable transformers do store some energy however.
  1. magnetizing inductance represents energy stored in the finite permeability of the magnetic core
  2. leakage inductance.
This is what I think happens.

When the 400 volts is presented to the primary of the transformer the spark starts and uses all the energy in the capacitor. This voltage also starts to charge the magnetizing inductance, the inductor in parallel with the ideal transformer in a model.

When the energy in the storage cap is depleted the magnetizing inductance continues to draw current from the node. This charges the .01 uF snubber capacitor.

When the current drops to zero the SCR shuts off and the fly back takes over and charges everything back up

wwest 12-15-2015 12:23 PM

The question Bob posited in post # 7 requires a non-simplistic response..

We'll get there...

Bob Kontak 12-15-2015 01:30 PM

Quote:

Originally Posted by wwest (Post 8919144)
The question Bob posited in post # 7 requires a non-simplistic response..

We'll get there...

It's ok if we don't get there. It was a really basic question and was not specific to CDI's. Perhaps poor placement by me.

It was an eleven year old with a new Heathkit kind of question by me.


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