Engine displacement changes

[RPMClassic]

What displacement do you end up when using 90mm Euro 2.7 liter P&C's,2.2 liter rods with a 66mm crank?? Thanks.

[Tim Walsh]

2.519L

[RPMClassic]

There is a car in my area that runs a 2.6 liter....trying to figure out how they got that with the crank and rods as posted. What if you swapped out 92mm P&C's with the other components listed.

[Tim Walsh]

92mm Pistons and a 66mm crank makes for 2.632L

[tholyoak]

The displacement is easy enough to calculate for any crank stroke and piston bore

1) calculate the volume of the swept cylinder
V=pi*r*r*h

Where pi=3.1415927
r*r is r (squared)(don't know how to do exponents here) = bore/2 in cm
h= the crank stroke in cm

This will give the volume of one cylinder,
2) multiply the above times 6 for the 6 cylinder engine or the number of cylinders for any other motor

3) this gives displacement in mL so divide by 1000 for displacement in L

in the above example

V=pi*4.5x4.5x6.6=419.87x6=2519.24=2.519L

or with 92 mm bore
V=pi*4.6x4.6x6.6=438.742x6=2632.45=2.632L

Todd

[RPMClassic]

Todd -

Looks like you're pretty good at math! Thanks for posting that info.

Jim